How do you differentiate #f(x)=x^6/(x-6)# using the quotient rule?
1 Answer
Aug 12, 2018
Explanation:
#"given "f(x)=(g(x))/(h(x))" then"#
#f'(x)=(h(x)g'(x)-g(x)h'(x))/(h(x))^2larrcolor(blue)"quotient rule"#
#g(x)=x^6rArrg'(x)=6x^5#
#h(x)=x-6rArrh'(x)=1#
#f'(x)=(6x^5(x-6)-x^6)/(x-6)^2#
#color(white)(f'(x))=(5x^6-36x^5)/(x-6)^2#
