# 28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. From this information, what is the density of iron?

Approx....$8 \cdot g \cdot m {L}^{-} 1$....
$\rho , \text{density"="Mass"/"Volume}$
$= \frac{28.5 \cdot g}{\left(49.10 - 45.50\right) \cdot m L} = 7.92 \cdot g \cdot m {L}^{-} 1$....