# 2NaN_3(s) -> 2Na(s) + 3N_2(g) Given the equation, how many moles of N_2 are produced by the decomposition of 1.50 mol of NaN_3?

The equation tells you that for every 2 moles of $N a {N}_{3}$ decomposed, you get 3 moles of ${N}_{2}$ out.