3/(y^2-9) + 4/(y+3) =1? P.S. I don't know how to do this can you please give me a answer right now when you are finished this problem?

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Answer 1 · 2017-03-17T00:17:32

#y=0# and #y=4#

The equation

#3/((y-3)(y+3))+4/(y+3)=1# can be solved first by multiplying both equation sides by #y+3#. After that we obtain

#3/(y-3)+4=(y+3)#

multiplying both sides by #(y-3)# we obtain

#3+4(y-3)=y^2-9# or

#y^2-4y=0# or

#y(y-4)=0# giving the solutions

#y = 0# and #y=4#