# Question #9e481

Dec 9, 2014

The answer is $4.0 g$.

We know that molarity is the concentration of a solution expressed by the number of moles of solute per liter of solution. This means that

$C = {n}_{s o l u t e} / \left({V}_{s o l u t i o n}\right) \to {n}_{H C l} = C \cdot {V}_{s o l u t i o n}$

So, ${n}_{H C l} = 1.5 \frac{m o l e s}{L} \cdot 75 \cdot {10}^{- 3} L = 0.11 m o l e s$

Knowing that $H C l$'s molar mass is equal to $36.5 \frac{g}{m o l}$, we can determine its mass by

${m}_{H C l} = {n}_{H C l} \cdot 36.5 \frac{g}{m o l} = 0.11 m o l e s \cdot 36.5 \frac{g}{m o l e} = 4.0 g$