Question #95964

1 Answer
Dec 10, 2014

You need to start by using the definition of molarity to determine how many moles of #HCl# can be found in #75mL# of solution.

#n_(HCl) = C * V_(solution) = 1.50 (mol es)/L * 75 * 10^(-3) L = 011 mol es#

Now, knowing that #HCl#'s molar mass is #36.5 g/(mol e)#, we can determine the mass of #HCl# dissolved in #75mL# by

#m_(HCl) = n_(HCl) * 36.5 g/(mol e) = 0.11 mol es * 36.5 g/(mol e) = 4.0 g#