# Question 27f47

Jan 17, 2015

The answer is $1.66$ $\text{cm}$

So, start with the fact that you have $2.6 \cdot {10}^{23}$ atoms of TI, which will allow you to determine how many moles you actually have

$2.6 \cdot {10}^{23}$ "atoms" * ("1 mole Ti")/("6.022" * 10^23 "atoms") = 0.43 $\text{moles}$

From here, use $\text{Ti}$'s molar mass to find out how many grams you have.

$\text{0.43 moles" * ("47.9 grams")/("1 mole Ti") = "20.6 grams}$

Use the given density to determine the volume you have

rho = m/V => V = m/(rho) = ("20.6 g")/("4.50 g/cm"^3) = "4.58 cm"^3

Since you're dealing with a cube, which has a volume of V_("cube") = "edge"^3#, your edge length will be

$\text{edge" = V^(1/3) = "1.66 cm}$