# Question #2af22

Feb 18, 2015

The new volume will be $\text{122 mL}$, or $\text{0.122 L}$.

Once again, this is an application of Boyle's law. At constant temperature, pressure and volume have an inverse relationship.

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

You start with $\text{259 mL}$ and $\text{690. mmHg}$, which will represent ${V}_{1}$ and ${P}_{1}$. You know that the pressure in the new container is $\text{1470 mmHg}$. Even before calculating the actual volume, you can estimate what it will be.

Notice that the new pressure is approximately twice as big as the old pressure, which implies that the new volume must be approximately half of the old volume.

${V}_{2} = {P}_{1} / {P}_{2} \cdot {V}_{1} = \text{690. mmHg"/("1470 mmHg") * "259 mL" = "122 mL}$, or

${V}_{2} = \text{0.122 L}$