Question #d1001

1 Answer
Jun 16, 2015

Answer:

You draw concentric circles, each with the appropriate number of electrons.

Explanation:

Sodium Oxide

The electron configuration of #"Na"# is (2, 8, 1). It can achieve a noble gas octet by donating its outer electron to another atom.

The electron configuration of #"O"# is (2, 6). It can achieve a noble gas octet by accepting an electron from each of two sodium atoms (excuse my hand-drawn diagrams).

Na2O

The opposite charges create electrostatic attractions between the #"Na"^+# and #"O"^(2-)# ions.

Calcium Sulfide

The electron configuration of #"Ca"# is (2, 8, 8, 2). It can achieve a noble gas octet by donating its two outer electrons to another atom.

The electron configuration of #"S"# is (2, 8, 6). It can achieve a noble gas octet by accepting two electrons into its outer shell.

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The opposite charges create electrostatic attractions (ionic bonds) between the #"Ca"^(2+)# and #"S"^(2-)# ions.

Hydrogen Bromide

The electron configuration of #"H"# is (1). It can achieve a helium configuration by sharing its outer electron with another atom.

The electron configuration of #"Br"# is (2, 8,18, 7). It can achieve a noble gas octet by sharing an outer electron with #"H"#.

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The sharing of electrons makes a covalent bond.

Ethene

The electron configuration of #"H"# is (1). It can achieve a helium configuration by sharing its outer electron with another atom.

The electron configuration of #"C"# is (2, 6). It can achieve a noble gas octet by sharing its outer electrons with other atoms.

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The sharing of two electrons makes a covalent #"C-H"# bond. the sharing of four electrons makes a covalent #"C=C"# double bond.