Question #31ade

1 Answer
May 22, 2015

You can add a solution of potassium iodide, #KI#.

The balanced chemical equation for this double replacement reaction would look like this

#Pb(NO_3)_(2(aq)) + 2KI_text((aq]) -> 2KNO_(3(aq)) + PbI_(2(s)) darr#

Lead (II) iodide is a yellow precipitate that will be formed in the reaction.

The ney ionic equation, which you get if the spectator ions are removed, looks like this

#Pb_((aq))^(2+) + 2I_((aq))^(-) -> PbI_(2(s)) darr#

Here's a video of the reaction: