Question #57654

1 Answer
Jun 9, 2015

Answer:

About #"5 N"# [down the incline].

Explanation:

The force acting on the object is equal to the object's weight #mg#

On an incline, this force is divided into two components.

Component 1 directed into the incline = #mgcostheta#

This force is balanced by the normal force (the supporting force exerted by the incline on the object)

http://www.sparknotes.com/testprep/books/sat2/physics/chapter8section8.rhtml

Component 2 is parallel to the incline = #mgsintheta#

This is the unbalanced (net force) on the object--take #g = "10 m s"^(-2)#

#F_"net"=mgsintheta =(2)(g)5/20 = "5 N"#