# How do we find the latus rectum of the parabola #y=2x^2#?

##### 1 Answer

Jul 28, 2017

#### Answer:

Latus rectum is

#### Explanation:

Vertex form of equation of paarbola is **In the equation #y=a(x-h)^2+k#, focus is #(h,k+1/(4a))# and directrix is**

As such for

focus are

As

and latus rectum is

graph{(y-2x^2)(x^2+(y-1/8)^2-0.0001)((x+1/4)^2+(y-1/8)^2-0.0001)((x-1/4)^2+(y-1/8)^2-0.0001)=0 [-0.628, 0.622, -0.0875, 0.5375]}