# Question 2567f

Jun 27, 2015

24.5m

#### Explanation:

To get the height the ball reaches above the plaza we can use:

$s = u t + \frac{1}{2} \text{g} {t}^{2}$

It will take 4/2 = 2s to reach its zenith.

$\text{g"=-9.8"m/s}$

$s = 19.6 \times 2 + \frac{1}{2} \text{g} {2}^{2}$

$= 39.2 - 19.6 = 19.6 \text{m}$

We can get the total distance the ball falls using:

S_("tot")=1/2"g"t^(2)#

This time $\text{g"=+9.8"m/s}$

and the total time = $2 + 1 = 3 s$

${S}_{\text{tot")=1/2"g"9=(9"g}} / 2$

If the height of the tower is $h$ then:

$19.6 + h = \frac{9 \text{g}}{2}$

$h = 44.1 - 19.6 = 24.5 \text{m}$