# Question #a288d

##### 1 Answer

#### Answer:

The answer is **(c)** *decreases*.

#### Explanation:

The idea behind this problem is that Earth's roration produces a **centripetal acceleration**, which is directed towards the center of rotation, that *reduces* the gravitational acceleration,

This centripetal acceleration is defined by the equation

*angular velocity* of the Earth;

The force that creates this centripetal acceleration is called the **centripetal force** and is pointed towards the center of ration as well.

Now, an object that is in a *rotating reference frame*, i.e. a reference frame that is rotating with the system, will be acted upon by the *centrifugal force*.

This "force" (it is not a force *per se*) points **outwards** from the center of rotation and actually replaces the centripetal force.

This means that, for a person that's rotating at the equator, this centifugal force will actually **oppose** gravity.

This means that the weight of the person *at the equator* will actually be

For future reference, *acceleration due to gravity at the equator*.

As you can see, the magnitude of

This **bigger** **smaller**

As a conclusion, the **faster** the Earth spins, the **lower** **decreases**.