# Question #8b7fa

##### 1 Answer

The object is at a height of

#### Explanation:

So, you know that your object is being released from a height

This means that you can write

#h = underbrace(v_0)_(color(blue)(=0)) * t + 1/2 * g * t^2#

Now, let's assume that we can stop this object's motion at

#h_1 = underbrace(v_0)_(color(blue)(=0)) * t/2 + 1/2 * g * (t/2)^2#

#h_1 = 1/2 * g * t^2/4#

Notice that

#h_1 = underbrace(1/2 * g * t^2)_(color(blue)(=h)) * 1/4 = 1/4 * h#

Well, if the object travelled **from the ground** is

#h_"from ground" = h - h_1#

#h_"from ground" = h - h * 1/4 = color(green)(3/4 * h)#