# How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

Sep 26, 2015

$D B E = 2$

In other words, the molecule has 2 degrees of unsaturation.

#### Explanation:

The molecular formula of 2,2,3,3-tetramethyl-4-octyne is ${C}_{12} {H}_{22}$

The general formula for calculating the double bond equivalent (DBE) is:

$D B E = C - \frac{H}{2} + \frac{N}{2} + 1$

where, $C$ is the number of carbon atoms, $H$ is the number of hydrogen and halogen atoms, and $N$ is the number of nitrogen atoms if there is any in the molecule.

Therefore, in this case:

$D B E = 12 - \frac{22}{2} + \frac{0}{2} + 1 = 2$

It is logic to find $D B E = 2$ since we have two $\pi$ bonds in a triple bond.