# Question #62d9c

##### 1 Answer

#### Explanation:

You can break the motion of the ball into two parts

*moving upwadrs from the height of the tower while being decelerated by the gravitational acceleration**free falling from maximum height*.

At **maximum height**, the velocity of the ball is equal to **zero**. This means that you an say

#underbrace(v_"top"^2)_(color(blue)(=0)) = v_0^2 - 2 * g * h" "# , where

**from the initial position**.

You get that

#h = v_0^2/(2 * g) = (19.6""^2"m"^color(red)(cancel(color(black)(2)))color(red)(cancel(color(black)("s"^2))))/(2 * 9.8color(red)(cancel(color(black)("m")))/color(red)(cancel(color(black)("s"^2)))) = "19.6 m"#

The *time it took* to reach maximum height, i. e. travel

#underbrace(v_"top")_(color(blue)(=0)) = v_0 - g * t_"up"#

#t_"up" = v_0/g = (19.6color(red)(cancel(color(black)("m")))/color(red)(cancel(color(black)("s"))))/(9.8color(red)(cancel(color(black)("m")))/"s"^color(red)(cancel(color(black)(2)))) = "2 s"#

So, it climbs for **two seconds**, and its **total flight time** is **six seconds**, then that must mean that it fell from maximum height in **four seconds**

#t_"down" = t_"total" - t_"up"#

#t_"down" = "6 s" - "2 s" = "4 s"#

This means that maximum height,

#H = underbrace(v_"top")_(color(blue)(=0)) * t_"down" + 1/2 * g * t_"down"^2#

#H = 1/2 * 9.8"m"/color(red)(cancel(color(black)("s"^2))) * 4""^2color(red)(cancel(color(black)("s"^2))) = "78.4 m"#

The height of the tower was

#h_"tower" = H - h#

#h_"tower" = "78.4 m" - "19.6 m" = color(green)("58.8 m")#