Question #6c7bc

1 Answer
Feb 11, 2016

Answer:

To answer this question, your need to know that some organic compounds may undergo acid-base reactions which enhances their solubility in water.

Explanation:

To outline the separation scheme, first you need to know first the structure of the compounds in the problem:enter image source here

For the separation scheme, first dissolve the components of the mixture with an organic solvent like dichloromethane so that a solution will result . In order to remove aniline from the mixture, you may add an aqueous solution of HCl to convert it to its protonated form which enhances its solubility with water.

Upon addition of the acid, you will notice that two layers will be formed. You can separate the two layers using a separatory funnel. The aqueous layer (the layer which is miscible in water) will contain the protonated form of aniline while the organic layer (the layer which is immiscible in water) contains naphthol and p-dichlorobenzene. To revert back aniline to its original form, you may add an aqueous solution of NaOH to the aqueous layer, obtain the organic layer using a separatory funnel from the resulting mixture, and perform distillation to remove dichloromethane.

enter image source here

Then to separate napthol and p-dichlorobenzene with each other (remember they are still dissolved in the first organic layer), you may add an aqueous solution of NaOH in order to deprotonate napthol and increase it solubility in water. After doing so, you may notice the formation of two distinct layers.

After separating the aqueous solution (which contains deprotonated naphthol) with the organic layer (which contain p-dichlorobenzene) using a separatory funnel, you can precipitate out napthol from the aqueous layer by addition of aqueous solution of HCl. This will revert back napthol to its original form. The solids formed can be isolated by filtration.

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Finally to obtain p-dichlorobenzene, distillation to remove dichloromethane should be done.