# Question #c42a5

Nov 3, 2015

a) non polar covalent; b) polar covalent; c) non polar covalent; d) non polar covalent; e) non polar covalent; f) non polar covalent; h) same as (f); i) non polar covalent

#### Explanation:

You can use is the electronegativity values to predict what kind of chemical bond would the elements undergo to.

If the difference in electronegativities between two bonding elements is less than 0.5, then you have a nonpolar covalent bond.

If the difference in electronegativities between two bonding elements is between 0.5 and 1.6, then you have a polar covalent bond.

If the difference in electronegativities between two bonding elements is greater than 2, then you have an ionic bond.

In your question, the electronegativities of the elements are as follows: $H$ = 2.1 ; $O$ = 3.4 ; $C$ = 2.5 ; $N$ = 3.0

Thus,
a) 2.1 - 2.1 = 0, non polar covalent
b) 3.4 - 2.1 = 1.3, polar covalent
c) 3.4 - 2.5 = 0.9, non polar covalent
d) 3.0 - 2.1 = 0.9, non polar covalent
e) 3.0 -3.0 = 0, non polar covalent
f) 2.5 - 2.1 = 0.4, non polar covalent
h) same as (f)
i) 2.5 - 2.5 = 0, non polar covalent