A gas occupies 1.0 liter at 1.2 atm. What is the pressure if the volume is increased to 4.0 liters?

Nov 23, 2015

The final pressure will be $\text{0.30 atm}$.

Explanation:

Boyle's law states that when temperature and mass is kept constant, the volume of a gas varies inversely with pressure. The equation for this law is ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$.

Given
${P}_{1} = \text{1.2 atm}$
${V}_{1} = \text{1.0 L}$
${V}_{2} = \text{4.0 L}$

Unknown
${P}_{2}$

Solution
Rearrange the equation to isolate ${P}_{2}$ and solve.

${P}_{2} = \frac{{P}_{1} {V}_{1}}{{V}_{2}}$

P_2=((1.2"atm"xx1.0"L"))/(4.0"L")="0.30 atm"