A gas occupies $1.0$ $1.0$ liter at $1.2$ $1.2$ atm. What is the pressure if the volume is increased to $4.0$ $4.0$ liters?

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A gas occupies $1.0$ $1.0$ liter at $1.2$ $1.2$ atm. What is the pressure if the volume is increased to $4.0$ $4.0$ liters?

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Answer 1 · 2015-11-23T01:38:45

The final pressure will be $0.30 atm$ $"0.30 atm"$ .

Explanation:

Boyle's law states that when temperature and mass is kept constant, the volume of a gas varies inversely with pressure. The equation for this law is $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ .

Given
$P_{1} = 1.2 atm$ $P_1="1.2 atm"$
$V_{1} = 1.0 L$ $V_1="1.0 L"$
$V_{2} = 4.0 L$ $V_2="4.0 L"$

Unknown
$P_{2}$ $P_2$

Solution
Rearrange the equation to isolate $P_{2}$ $P_2$ and solve.

$P_{2} = \frac{P_{1} V_{1}}{V_{2}}$ $P_2=(P_1V_1)/(V_2)$

$P_{2} = \frac{(1.2 atm \times 1.0 L)}{4.0 L} = 0.30 atm$ $P_2=((1.2"atm"xx1.0"L"))/(4.0"L")="0.30 atm"$

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A gas occupies $1.0$ $1.0$ liter at $1.2$ $1.2$ atm. What is the pressure if the volume is increased to $4.0$ $4.0$ liters?

1 Answer

Explanation:

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A gas occupies $1.0$ $1.0$ liter at $1.2$ $1.2$ atm. What is the pressure if the volume is increased to $4.0$ $4.0$ liters?