# Question 7db3d

Dec 19, 2015

$330 , 875 K = 57 , {725}^{\circ} C$

#### Explanation:

From the general gas equation $p V = n R T$, we get that

$T = \frac{p V}{n R}$

Inserting all the values with correct SI units, with $R$ the general gas constant having value $8 , 31$ units, yields

T= ((734425Pa)(0,00152m^3))/((0,406mol)(8,31)#

$= 330 , 875 K$

$= 57 , {725}^{\circ} C$