Question #bafc0

1 Answer
Dec 14, 2015

Answer:

#0,0017mol#

Explanation:

Since concentration is moles per unit volume (#c=n/V#), and moles is mass over molar mass (#n=m/(M_r#), we may combine the two to obtain that

#c=m/(M_r*V)#

#therefore m=c*M_r*V#

#=2,28mol//dm^3xx(39+80)g//molxx0,00075dm^3#

#=0,2035g#.

This corresponds to the following number of moles :

#n=m/(M_r)=(0,2035g)/(119g//mol)=0,0017mol#.