# Question ba858

Jan 11, 2016

$1510 g {C}_{3} {H}_{8}$

#### Explanation:

From the energy released and the molar enthalpy we can find the number of mole of propane that needs to be used;

?mol C_3H_8=76000cancel(KJ)xx(1molC_3H_8)/(2219cancel(KJ))=34.25 molC_3H_8

To find the mass of propane needed:

?gC_3H_8=34.25cancel("mol "C_3H_8)xx(44.10gC_3H_8)/(1cancel("mol "C_3H_8))=1510 gC_3H_8#