569 g salt water solution is added to a beaker. If the solution has a density of 1.19 g/mL, what is the volume of this solution?

1 Answer
Sep 23, 2016

Answer:

Approx. #475*mL#

Explanation:

#rho,"density"# #=# #"Mass"/"Volume"#

Thus, #"volume"# #=# #"Mass"/rho# #=# #(569*cancelg)/(1.19*cancelg*mL^-1)# #=# #??mL#.

Note the dimensional consistency. I wanted a volume; and the units of the calculation cancelled to give me an answer in #"millilitres"# (or rather in #1/(mL^-1)=mL#). This persuades me that I set up the problem correctly; it's all too east to make a mistake.