# 569 g salt water solution is added to a beaker. If the solution has a density of 1.19 g/mL, what is the volume of this solution?

Sep 23, 2016

Approx. $475 \cdot m L$
$\rho , \text{density}$ $=$ $\text{Mass"/"Volume}$
Thus, $\text{volume}$ $=$ $\frac{\text{Mass}}{\rho}$ $=$ $\frac{569 \cdot \cancel{g}}{1.19 \cdot \cancel{g} \cdot m {L}^{-} 1}$ $=$ ??mL.
Note the dimensional consistency. I wanted a volume; and the units of the calculation cancelled to give me an answer in $\text{millilitres}$ (or rather in $\frac{1}{m {L}^{-} 1} = m L$). This persuades me that I set up the problem correctly; it's all too east to make a mistake.