# Question #3bc00

Mar 19, 2016

NO will diffuse more quickly

#### Explanation:

Thomas Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of the particles.
So the gas having less molar mass will diffuse more quickly
In our case
Molar mass of ${H}_{2} S = 2 \times 1 + 32 = 34$
Molar mass of $N O = 14 + 16 = 30$
Molar mass of $C {l}_{2} = 2 \times 35.5 = 71$
Molar mass of ${N}_{2} O = 2 \times 14 + 16 = 44$

Hence NO will diffuse more quickly