Question

Question #db42e

Answer 1

Let the mass of the moon be `Mkg`

Radius of the moon be `R=1.74xx10^6m`

Acceleration due to gravity of moon surface be `g_"moon"=1.67ms^-2`

Gravitational constant be `G=6.674xx 10^-11 m^3 kg^-1s^-2`

considering the force of attraction on a mass of `mkg` kept on its surface we can write

`mg_"moon"=(GMm)/R^2`

`=>M=(g_"moon"R^2)/G`

`=(1.67ms^-2xx(1.74xx10^6m)^2) /(6.674xx 10^-11 m^3 kg^-1s^-2)=7.576xx10^22kg`