# Question #ddcf4

Mar 1, 2016

1.29 L

#### Explanation:

Boyle's Law states that ${P}_{1} {V}_{1}$ = ${P}_{2} {V}_{2}$

you are given ${P}_{1}$ (1.1 atm) and ${V}_{1}$ (4.0L)

you want ${P}_{2}$ to be 3.4 atm; plug everything in and you get

$\left(1.1 a t m\right) \cdot \left(4.0 L\right)$ = $\left(3.4 a t m\right) \cdot \left(x L\right)$

Rearrange to solve for x

$\frac{\left(1.1 a t m\right) \cdot \left(4.0 L\right)}{3.4 a t m}$ = $1.29 L$