Question #6158f

2 Answers
May 27, 2017

Answer:

#n=6 or n=4#

Explanation:

  • The first step with a quadratic equation is to make it equal to #0#

#n^2 -10n+22 = -2#

#n^2 -10n +24=0#

  • The second step is to factorise if possible.

The #+# with #24# tells you that you must find factors of #24# which ADD up to #10#

#6and 4# will work: #6 xx 4 = 24" and "6 +4 =10#

The #+# with #24# also tells you that the signs of the factors must be the same.

The #-# with #10# tells you that the signs will both be #"negative"#

#n^2 -10n +24=0#

#(n-6)(n-4)=0#

  • The third step is to set each factor equal to #0# and solve it.

#n-6 =0" "rarr n=6#
#n-4 =0" "rarr n=4#

Jul 8, 2017

Answer:

4, and 6

Explanation:

#f(n) = n^2 - 10n + 24 = 0#
Use the new Transforming Method (Google Search), when a = 1.
Find 2 real roots, that have same sign (ac > 0), knowing the sum (-b = 10) and the product (c = 24). They are 4 and 6.
Answers: 4 and 6.

NOTE. No need to go further in factoring by grouping and solving the 2 binomials.