# Question #3b5f1

Mar 12, 2016

$11.2 g$
ok so first you will find the moles in 16.5g of $F {e}_{2} {O}_{3}$
by putting the values $m o l = \frac{16.5}{160}$ the mols will be $0.1$
so by using the equation we know that 1 mol of $F {e}_{2} {O}_{3}$ makes
2 mols of $F e$ so by using the ratio method $1 : 2$ and $0.1 : x$ write these one above the other and cross multiply so the mols of $F e$ we will get will be $0.2$ then use the formula moles=mass/molar relative mass $0.2 \cdot 56 = m a s s$ the ans will be $11.2 g$