# Question #d09d7

Mar 14, 2016

$0.20 M$

#### Explanation:

The molarity (${C}_{M}$) of a solute (oxalic acid) in an aqueous solution is found by:

${C}_{M} = \frac{n}{V}$

where, $n$ is the number of mole of oxalic acid, $V = 0.250 L$ is the volume of the solution.

The number of mole $n$ is found by: $n = \frac{m}{M M}$

where, $m = 6.3 g$ is the mass of oxalic acid, and $M M = 126 \frac{g}{m o l}$ is the molar mass of the oxalic acid.

$\implies n = \frac{m}{M M} = \frac{6.3 \cancel{g}}{126 \frac{\cancel{g}}{m o l}} = 0.050 m o l$

Thus, ${C}_{M} = \frac{n}{V} = \frac{0.050 m o l}{0.250 L} = 0.20 M$

Here is a video on how to prepare a solution.
Lab Demonstration | Solution Preparation & Dilution.