Question #d09d7

1 Answer
Mar 14, 2016

Answer:

#0.20M#

Explanation:

The molarity (#C_M#) of a solute (oxalic acid) in an aqueous solution is found by:

#C_M=n/V#

where, #n# is the number of mole of oxalic acid, #V=0.250L# is the volume of the solution.

The number of mole #n# is found by: #n=m/(MM)#

where, #m=6.3g# is the mass of oxalic acid, and #MM=126g/(mol)# is the molar mass of the oxalic acid.

#=>n=m/(MM)=(6.3cancel(g))/(126cancel(g)/(mol))=0.050mol#

Thus, #C_M=n/V=(0.050mol)/(0.250L)=0.20M#

Here is a video on how to prepare a solution.
Lab Demonstration | Solution Preparation & Dilution.