Question

Question #0facc

Answer 1

`(x^2+y^2)=3sqrt(x^2+y^2)-x`

Explanation:

Use the conversion formula `r(cos theta, sin theta )=(x, y)`,

where `r = sqrt(x^2+y^2)>=0`.

After substitutions and rearrangement,

Seemingly a circle, the graph is for a limacon that has an invisible

dent, on the right.

`(x^2+y^2)=3sqrt(x^2+y^2)-x`.

graph{x^2+y^2-3sqrt(x^2+y^2)+x=0 [-10, 10, -5, 5]}