Apr 19, 2016

0.8 mol

Explanation:

As per the equation

${H}_{2}$ (g) + ${O}_{2}$ (g) -----> 2${H}_{2}$O (l)

1 mol of ${O}_{2}$ is required to produce 2 moles of ${H}_{2}$O

x mol of ${O}_{2}$ is required to produce 1.60 moles of ${H}_{2}$O

setting up the ratio , we get

(1 mol of ${O}_{2}$ / X mol of ${O}_{2}$) = (2 mol of ${H}_{2}$O / 1.6 mol of ${H}_{2}$O)

1 / x = 2 /1.6

1 x 1.6 = 2.x

1.6 = 2x

x= 0.8 mol