Question #7c5e0

1 Answer
Jul 10, 2016

Given

#f="The focal length of convex mirror"= 20 cm#

#u="Object distance"=-6m=-600 cm#

#v="Image distance"=?#

#h_o="Height of the object"1.6m#

#w_o="Width of the object"=2m#

#color(blue)("The Mirror Formula":#

#color(red)(1/v+1/u=1/f)#

#=>1/v-1/600=1/20#

#=>1/v=1/20+1/600=31/600#

#=>v=600/31~~20cm#

#m="Magnification"=-v/u=1/31#

So

#h_i="Height of the image"=mxxh_o=160/31cm#

#h_i="Width of the image"=mxxw_o=200/31cm#

So the image of the car will be seen #~~20 cm# behind the mirror and its height will be #160/31cm# and its width will be #200/31cm#