# Question #cdacb

If $y = \left(- 3 x\right) + 5$
then it will have points in the first quadrant provided there is at least one point $\left(x , y\right)$ with $x > 0$ and $y > 0$ which satisfies this equation.
Note that is $x = 1$ then $y = 2$
So $\left(x , y\right) = \left(1 , 2\right)$ is a point that satisfies this equation and is in the first quadrant.