Question

What is the rectangular coordinate form of the polar coordinates `(r, pi/6)` ?

Answer 1

`(r, pi/6)` in polar form is `(sqrt(3)/2 r, r/2)` in rectangular form

Explanation:

`theta = pi/6` only gives you the angle.

You need a radius too, but `(r, pi/6)` in polar form is `(sqrt(3)/2r, r/2)` in rectangular form.

`pi/6` is one half of an internal angle of an equilateral triangle.