Question

Simplify `(cscxcosx)/(tanx+cotx)`?

Answer 1

Please see below.

Explanation:

`(cscxcosx)/(tanx+cotx)`

= `(cscxcosx)/(sinx/cosx+cosx/sinx)`

= `(cscxcosx)/((sin^2x+cos^2x)/(cosxsinx))`

= `(cscxcosx)/(1/(cosxsinx))`

= `cscxcosx xxcosxsinx`

= `cos^2x xx cscxsinx`

= `cos^2x xx1=cos^2x`