Question #68f30
1 Answer
Explanation:
That is
#sin((2pi)/3+(5pi)/4) = sin((2pi)/3)cos((5pi)/4) + cos((2pi)/3)sin((5pi)/4)#
#= sqrt3/2 (-sqrt2/2) + (-1/2)(-sqrt2/2)#
#= (sqrt2 - sqrt6)/4#
thus
#csc((2pi)/3+(5pi)/4) = 4/(sqrt2 - sqrt6) = -4 * (sqrt2 + sqrt6)/4 = -sqrt2 - sqrt6#
Note