# Question #7e002

Apr 28, 2016

$\textcolor{red}{2} N a C l + {H}_{2} S {O}_{4} = N {a}_{2} S {O}_{4} + \textcolor{red}{2} H C l$

#### Explanation:

Since we have $N {a}_{\textcolor{red}{2}} S {O}_{4}$ on the right side
the left side must have a multiple of $\textcolor{red}{2}$ $N a C l$'s

Trying the minimum of $\textcolor{red}{2} N a C l$ on the left implies we will need to have a multiple of $\textcolor{red}{2} \textcolor{w h i t e}{\text{ }} C l$'s in $H C l$ on the right;

but the ${H}_{\textcolor{red}{2}}$ in the ${H}_{2} S {O}_{4}$ on the left provides the $\textcolor{red}{2} H$'s needed for $\textcolor{red}{2} H C l$ to work out.