# Question 2a02f

May 10, 2016

There is insufficient information to give a complete answer to this question.

#### Explanation:

Without knowing the cross-sectional area of the measuring cylinder
we can not calculate the volume of the stone and therefore we can not calculate the stone's density.

If the cross-sectional area of the measuring cylinder is $a {\text{ cm}}^{2}$
then the volume of the stone would be
color(white)("XXX") (68-40)" cm" xx a " cm"^3 = 28a " cm"^3
and its density would be
$\textcolor{w h i t e}{{\text{XXX")(50" grams")/(28a"cm}}^{3}}$

color(white)("XXX")=25/(14a) " gm/cubic cm"#