Question

Question #2a02f

Answer 1

There is insufficient information to give a complete answer to this question.

Explanation:

Without knowing the cross-sectional area of the measuring cylinder
we can not calculate the volume of the stone and therefore we can not calculate the stone's density.

If the cross-sectional area of the measuring cylinder is `a" cm"^2`
then the volume of the stone would be
`color(white)("XXX") (68-40)" cm" xx a " cm"^3 = 28a " cm"^3`
and its density would be
`color(white)("XXX")(50" grams")/(28a"cm"^3)`

`color(white)("XXX")=25/(14a) " gm/cubic cm"`