# Question b3655

Aug 11, 2016

$0.25 a t m$

#### Explanation:

The formula below will be used as a reference:

Identify the known and unknown variables.

color(red)("Knowns:"
${P}_{1}$= 1.00 atm
${V}_{1}$= 0.5 L
${V}_{2}$= 2.0 L

color(maroon)("Unknowns:"#
${P}_{2}$

Rearrange the equation to solve for the final pressure by dividing both sides by ${V}_{2}$ to get ${P}_{2}$ by itself like this:

${P}_{2} = \frac{{P}_{1} \times {V}_{1}}{V} _ 2$

Plug in your given values to obtain the final pressure:

${P}_{2} = \left(1.00 \setminus a t m \times 0.5 \setminus \cancel{\text{L")/(2.0\cancel"L}}\right)$ = $0.25 a t m$