A substance's density tells you the mass of one unit of volume of that substance.
In your case, the density of corn oil is said to be equal to
This means that for every
You can thus use the density of corn oil as a conversion factor to help you determine how many milliliters are equivalent to
#500 color(red)(cancel(color(black)("g"))) * overbrace("1 mL"/(0.92color(red)(cancel(color(black)("g")))))^(color(blue)("the density of corn oil")) = "543.8 mL"#
You should round this off to one sig fig, the number of sig figs you have for the mass of corn oil, but I'll leave it rounded to two sig figs
#"volume" = color(green)(|bar(ul(color(white)(a/a)color(black)("540 mL")color(white)(a/a)|)))#