Question #d0666

Question

1563 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-04T10:51:10

#-130kJmol^"-1"#

#DeltaH_"reaction"=H_"product"-H_"reactant"....(1)#

#DeltaE_"activation"=E_"TS"-H_"reactant"....(2)#

Energy released during bond formation

#DeltaH_"bond formation"=H_"product"-E_"TS"#

Subtracting (2) rom(1) We get

#DeltaH_"reaction"-DeltaE_"activation"=H_"product"- E_"TS"=DeltaH_"bond formation"#

Given

#DeltaH_"reaction"=53kJmol^"-1"#

#DeltaE_"activation"=183kJmol^"-1"#

#:.DeltaH_"bond formation"=(53-183)kJmol^"-1"=-130kJmol^"-1"#