# Question #9387b

##### 1 Answer

May 22, 2016

First simplify

#100int_0^1x^9f(x^10)dx=100/10int_0^1f(x^10)10x^9dx=10int_0^1f(u)du#

Note that the bounds did change, but not noticeably, since

Also note that

So, we see the value of

#"....."+100int_0^1x^9f(x^10)dx="....."+10int_0^1f(x)dx="....."+50#

I'm not really sure what the