Question

Question #064f8

Answer 1

`(5sqrt2,-1.429)`

Explanation:

Using the formulae that links Cartesian to Polar coordinates.

`•r=sqrt(x^2+y^2)" and " theta=tan^-1(y/x)`

here x = 1 and y = -7

`rArrr=sqrt(1^2+(-7)^2)=sqrt50=5sqrt2`

and `theta=tan^-1(-7)≈-1.429" radians"" or" ≈-81.87^@`

`rArr(1,-7)=(5sqrt2,-1.429)=(5sqrt2,-81.87^@)`