# Question #9a020

Jul 12, 2016

$p \left(- 2\right) = 12$

#### Explanation:

I am assuming that $p \left(x\right) = {x}^{3} + 7 {x}^{2} + 4 x$ and you want to find $p \left(- 2\right)$.

If this is the case, then plug in $- 2$ for all variables $x$.

$p \left(x\right) = {x}^{3} + 7 {x}^{2} + 4 x$

$p \left(- 2\right) = {\left(- 2\right)}^{3} + 7 {\left(- 2\right)}^{2} + 4 \left(- 2\right)$

$p \left(- 2\right) = - 8 + 28 - 8$

$p \left(- 2\right) = 20 - 8$

$p \left(- 2\right) = 12$