Question #88621

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Answer 1 · 2016-06-11T14:51:09

#E=6.626\times10^-18# J.

The energy of a photon, in quantum mechanics, is given by

#E=h\nu# where #\nu# is the frequency.
The relationship between frequency and wavelength is

#\nu=c/\lambda# where #c# is the speed of light and #\lambda# is the wavelength.

So the energy, as function of the wavelength is

#E=(hc)/lambda#.

It is now sufficient to substitute the numbers

#h=6.626\times10^-34# #J*s#

#c=3\times10^8# #m/s#

#\lambda=3*10^-8# #m#

#E=(6.626\times10^-34*3\times10^8)/(3\times10^-8)#

#=6.626\times10^(-34+8+8)#

#=6.626\times10^-18# J.