Question

Question #4cdbc

Answer 1

There are indeed 7 oxygen atoms in this equation.

Explanation:

I edited your question to make it more understandable. Maybe now you can see that there are indeed 7 oxygen atoms?

Lets first see how much of each element is in `2CO_2` :
you should read this as: `2*(C + O_2)`
which is similar to: `2*C + 2* (O+O)`
so there are `2` carbon atoms (`C`) and `2 * 2 = 4` oxygen (`O`) atoms.

Than the elements in the second part `3H_2O` :
this you should read as: `3* (H_2 + O)`
which is similar to: `3 * (H + H) + 3 * O`
so there are `6` hydrogen (`H`) atoms and `3` oxygen (`O`) atoms

In total: `4 * O` in `2CO_2` and `3 * O` in `3H_2O` = `7` oxygen atoms

Answer 2

There are seven Oxygen atoms in the reaction.

Explanation:

The numbers in front of the chemical formula indicate how many lots of that compund you have. The numbers apply to each element in the compound.

The example states:
`2CO_2+3H_2O`

If the numbers apply to each element, and there is a small subscript number next to it, then you multiply them together.

For example, `2CO_2`. Here there are 2 carbon atoms, as there is no number, which means that you only have one, and since there are 2 lots of `CO_2`, then you will have 2 carbon atoms and 4 oxygen atoms.

If we then apply this to the water molecules, we find that there are a total of 2 carbon atoms, 7 oxygen atoms, and 6 hydrogen atoms.