The figure above shown the position of the force vector whose #x# and #y# components are to be resolved.

(a) the #x# scalar component #F_x=Fcos 39^@#

Inserting value of #cos# from tables

#=>F_x=Fxx0.7771= 592xx0.7771#

#=460.0N#, rounded to one decimal place.

(b) #y# scalar component of the vector #F_y=-Fsin 39^@#

(#-ve# sign has been placed in front as the angle is in the fourth quandrant or #F_y# is in the #-y# direction).

Inserting value of #sin# from tables

#=>F_y=Fxx0.6293=592xx0.6293#

#= 372.6N#, rounded to one decimal place.