# Question df0fe

Jul 6, 2016

It is $0.555$ atm.

#### Explanation:

The equation of the perfect gas is

$P V = n R T$

$P$ is the pressure that we want to calculate, $V$ is the volume in ${\text{m}}^{3}$, $n$ are the mols, $R$ is the constant of perfect gas $8.314472 \left(\text{m"^3"Pa")/("mol" "K}\right)$, $T$ is the temperature in $\text{K}$.
First of all we need to transform our quantity in the proper units:

$V = 11.2 {\text{L"=11.2*10^-3 "m}}^{3}$

$T = {30}^{\setminus} \circ \text{C"=30+273.15 "K"=303.15"K}$.

The pressure is

P=(nRT)/V=(0.25 cancel"mol"*8.314472 (cancel("m"^3)"Pa")/(cancel"mol" cancel"K")*303.15cancel"K")/(11.2*10^-3 cancel("m"^3))#

$= \frac{0.25 \cdot 8.314472 \cdot 303.15}{11.2} \cdot {10}^{3} \text{Pa}$

$= 56261.88 \text{ Pa}$, or, if we want in a more familiar unit, we can convert it in atm using the conversion $1 \text{atm"=101325"Pa}$ then

$56261.88 \text{ Pa"= 56261.88/101325" atm}$

$= 0.555 \text{ atm}$.