# Question #11c25

Jul 11, 2016

Ammonia ($N {H}_{3}$)

#### Explanation:

Looking at molecular symmetry, you can see that the answer is $N {H}_{3}$.

$N {O}_{2}^{+}$ is linear, $A l C {l}_{3}$ is trigonal planar and $I C {l}_{4}$ is square planar, so any bond polarities will balance out overall giving no net dipole moment.

That leaves just ozone ${O}_{3}$ and ammonia. Ozone has a very small dipole moment as all 3 atoms are identical, and you just need to factor in the effect of the lone pair.

Ammonia on the other hand has 3 extremely polar bonds plus a lone pair. Dipole moment of around 3 D as opposed to ozone's value of about 0.5.